Answer
The equation of the line in slope-point form is
y + 3 = 0.2 (x + 4)
Thw equation of the line in slope-intercept form is
y = 0.2x - 2.2
Explanation
The general form of the equation in point-slope form is
y - y₁ = m (x - x₁)
where
y = y-coordinate of a point on the line.
y₁ = This refers to the y-coordinate of a given point on the line
m = slope of the line.
x = x-coordinate of the point on the line whose y-coordinate is y.
x₁ = x-coordinate of the given point on the line
For a straight line, the slope of the line can be obtained when the coordinates of two points on the line are known. If the coordinates are (x₁, y₁) and (x₂, y₂), the slope is given as
[tex]Slope=m=\frac{Change\text{ in y}}{Change\text{ in x}}=\frac{y_2-y_1}{x_2-x_1}[/tex]
For this question.
(x₁, y₁) and (x₂, y₂) are (-4, -3) and (6, -1)
[tex]\text{Slope = }\frac{-1-(-3)}{6-(-4)}=\frac{-1+3}{6+4}=\frac{2}{10}=0.2[/tex]
Recall,
y - y₁ = m (x - x₁)
(x₁, y₁) = (-4, -3)
x₁ = -4
y₁ = -3
m = Slope = 0.2
y - y₁ = m (x - x₁)
y - (-3) = 0.2 (x - (-4))
y + 3 = 0.2 (x + 4)
y + 3 = 0.2x + 0.8
y = 0.2x + 0.8 - 3
y = 0.2x - 2.2
Hope this Helps!!!
