Given data
*The given mass of the solid cylinder is m = 0.332 kg
*The given radius of the solid cylinder is r = 2.00 cm
*The given speed is v = 5.00 cm/s = 0.05 m/s
The formula for the total kinetic energy is given as
[tex]U_T=\frac{1}{2}I\omega^2+\frac{1}{2}mv^2[/tex]*Here I is the moment of inertia of the solid cylinder
Substitute the known values in the above expression as
[tex]\begin{gathered} U_T=\frac{1}{2}(\frac{1}{2}mr^2)\times(\frac{v}{r})^2+\frac{1}{2}mv^2 \\ =\frac{1}{4}mv^2+\frac{1}{2}mv^2 \\ =\frac{3}{4}mv^2 \\ =\frac{3}{4}(0.332)(0.05)^2 \\ =6.225\times10^{-4}\text{ J} \\ =0.6225\text{ mJ} \end{gathered}[/tex]