We will solve as follows:
[tex]\frac{2x+3}{9}>\frac{x}{3}+1\Rightarrow\frac{2}{9}x+\frac{1}{3}>\frac{x}{3}+1[/tex][tex]\Rightarrow\frac{2}{9}x-\frac{x}{3}>1-\frac{1}{3}\Rightarrow-\frac{x}{9}>\frac{2}{3}[/tex][tex]\Rightarrow x<-6[/tex]
So, the value that is a solution for the inequality is:
[tex]x=-10[/tex]
[Option A]
