Find the equation of the line that passes through the given point and has the given slope. (Use x as your variable.)(4, −3), m = −2

Respuesta :

General equation of line:

[tex]y=mx+c[/tex]

Where,

[tex]\begin{gathered} m=\text{slope} \\ c=y-\text{intercept} \\ (x,y)=(4,-3) \end{gathered}[/tex]

Slope of line is -2 then:

[tex]\begin{gathered} y=mx+c \\ y=-2x+c \end{gathered}[/tex][tex](x,y)=(4,-3)[/tex][tex]\begin{gathered} y=-2x+c \\ -3=-2(4)+c \\ -3=-8+c \\ 8-3=c \\ 5=c \end{gathered}[/tex][tex]\begin{gathered} y=mx+c \\ y=-2x+5 \end{gathered}[/tex]

Equation of line is y=-2x+5