Answer:
The measure of Angle A and B are;
[tex]\begin{gathered} m\measuredangle A=51^0 \\ m\measuredangle B=39^0 \end{gathered}[/tex]
Explanation:
Given that;
A ls 12° greater than the measure of B;
[tex]A=B+12\text{ ---------1}[/tex]
The two angles are complementary;
[tex]A+B=90\text{ -----2}[/tex]
Substituting equation 1 to 2, we have;
[tex]\begin{gathered} A+B=90 \\ (B+12)+B=90 \\ 2B+12=90 \\ 2B=90-12 \\ 2B=78 \\ B=\frac{78}{2} \\ B=39^0 \end{gathered}[/tex]
Substituting B into equation 1:
[tex]\begin{gathered} A=B+12 \\ A=39+12 \\ A=51^0 \end{gathered}[/tex]
Therefore, the measure of Angle A and B are;
[tex]\begin{gathered} m\measuredangle A=51^0 \\ m\measuredangle B=39^0 \end{gathered}[/tex]
