A)
starts off with 1000 and doubles every hour, so in 6 hours we will have 6 "doublings", Thus:
1000 * 2 * 2 * 2 * 2 * 2 * 2 = 64,000 bacteria
B)
the final population is 1,234,567. We can say:
[tex]1,234,567=1000\cdot2^x[/tex]Now, we solve for x:
[tex]\begin{gathered} 1234.567=2^x \\ \ln (1234.567)=\ln (2^x) \\ \ln (1234.567)=x\ln (2) \\ x=\frac{\ln (1234.567)}{\ln (2)} \\ x=10.27 \end{gathered}[/tex]t = 10.27 hours
