Given
[tex]\begin{gathered} -3x-4y=17 \\ -6x-4y=2 \end{gathered}[/tex]
Procedure
[tex]\begin{gathered} -3x-4y=17 \\ + \\ 6x+4y=-2 \\ \\ 6x-3x+4y-4y=17-2 \\ 3x=15 \\ x=\frac{15}{3} \\ x=5 \end{gathered}[/tex]
Now, solving for y
[tex]\begin{gathered} 6x+4y=-2 \\ 4y=-2-6x \\ y=\frac{-2-6x}{4} \\ y=\frac{-2-6\cdot5}{4} \\ y=\frac{-32}{4} \\ y=-8 \end{gathered}[/tex]The answer would be x = 5 and y = -8
