We have the following system of equations:
[tex]\begin{gathered} y=x-7\text{ (1)} \\ 5x+y=23\text{ (2)} \end{gathered}[/tex]I would solve it by the substituion method since we have that y=x-7, so we can substitute (1) in (2):
[tex]\begin{gathered} 5x+(x-7)=23 \\ 5x+x-7=23 \\ 6x-7=23 \\ 6x=23+7 \\ x=\frac{30}{6} \\ x=5 \end{gathered}[/tex]We find the solution for x, now we can substiute x=5 in (1) to find the solution for y:
[tex]\begin{gathered} y=x-7 \\ y=5-7 \\ y=-2 \end{gathered}[/tex]The solution of the system of equations is (5, -2).
