The length of a rectangle is four times its width.If the perimeter of the rectangle is 80 m, find its area

ANSWER
Area = 256 square meter
EXPLANATIONS
Step 1: Declaration of variables
Let W represent the width of the rectangle and L represent the length.
Step 2: Determine the width and the length
L = 4W ............equ (1)
[tex]\begin{gathered} Perimeter=2\mleft(L+W\mright)=80 \\ 2\mleft(4W+W\mright)=80 \\ 2(5W)\text{ = 80} \\ 10W\text{ = 80} \\ \text{Divide through by 10} \\ W\text{ = }\frac{80}{10} \\ W\text{ = 8m} \end{gathered}[/tex]from equ (1),
L = 4(8) = 32m
Step 3: Determine the Area
[tex]\text{Area of a rectangle = l}\ast w\text{ = 32}\ast8=256m^2[/tex]Hence, the Area of the rectangle is 256 square meter.