Respuesta :

[tex]3x^2+10x-8[/tex]

To factor an equation in the form:

[tex]ax^2+bx+c[/tex]

1. You can start by factor the term b as the add of two terms that multiplying give: -24

[tex]a\cdot c=3\cdot(-8)=-24[/tex]

and the adding = 10

in this case could be 12 and -2

you get:

[tex]3x^2+(12-2)x-8[/tex][tex]3x^2+12x-2x-8[/tex]

2. You can factor then finding the greatest common denominator by grouping the first two terms and the last two:

[tex](3x^2+12)-2x-8[/tex]

To the first two terms you have the gratest common denominator 3x and the second gruop -2

[tex]3x(x+4)-2(x+4)[/tex]

Then you finally factor the greatest common denominator:

The final factor is:[tex](x+4)(3x-2)[/tex]