[tex]\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{compounded amount}\\
P=
\begin{array}{llll}
\textit{original amount}\\
\textit{deposited}
\end{array}\to &\$14,800\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, meaning twice}
\end{array}\to &2\\
t=years\to &4
\end{cases} [/tex]
now, that will give you "A", or the compounded amount
what's the interest earned? well, subtract the original amount, the Principal, from A, A - P, and you'd be left with the earned interest
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[tex]\bf A=14,800\left(1+\frac{0.06}{2}\right)^{2\cdot 4}[/tex]
