estron7
contestada

Does anyone know how to find the unit vector of: v: <-6, -8> ?

It's either,
A.) <3/5, 4/5 >
B. <-3/5, -4/5 >
C.) <4/5, 3/5 >
D.) <-4/5, -3/5 >
Thanks.

Respuesta :

the unit vector, or a vector on the Unit Circle, has a magnitude of 1, thus is called a Unit vector :), in the Unit Circle, and is coterminal with  hmm in this case -6,-8, which has a bigger magnitude than 1

[tex]\bf \begin{array}{ccccllll} \ \textless \ &-6&,&-8\ \textgreater \ \\ &a&&b \end{array}\qquad \textit{so the vector }v\textit{ magnitude is} \\\\\\ ||v||=\sqrt{a^2+b^2}\implies ||v||=\sqrt{(-6)^2+(-8)^2}\implies ||v||=10 \\\\\\ \textit{thus the unit vector }v_o\textit{ will be}\implies \left(\frac{a}{||v||}, \frac{b}{||v||} \right) \\\\\\ or\implies \left( \frac{-6}{10},\frac{-8}{10} \right)\implies \left( \frac{-3}{5},\frac{-4}{5} \right)[/tex]