Solve.
{d+e=2d−e=4
Use the substitution method.

There are an infinite number of solutions.
There is no solution.
The solution is (3, −1).
The solution is (5, 1).

Question

22-02-2017
Mathematics

contestada

Solve.
{d+e=2d−e=4
Use the substitution method.

There are an infinite number of solutions.
There is no solution.
The solution is (3, −1).
The solution is (5, 1).

Respuesta :

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OrethaWilkison OrethaWilkison · Answer 1 · 2019-01-24T18:02:21+01:00

Answer:

Option C is correct.

The solution is (3, -1)

Step-by-step explanation:

Substitution

Given the system of equation:

[tex]d+e = 2[/tex] ......[1]

[tex]d-e = 4[/tex] ......[2]

We can write equation [2] as;

d = e +4 ....[3]

Using substitution method;

Substitute the value of d in equation [1] we have;

[tex]e+4+e = 2[/tex]

Combine like terms;

[tex]2e +4 = 2[/tex]

Subtract 4 from both sides, we get

2e = -2

Divide both sides by 2 we get;

e = -1

Substitute the value of e = -1 in [1] we have;

d +(-1) = 2

d -1 = 2

Add 1 to both sides of an equation;

d = 3

Therefore, the solution for the given system of equation is, (3, -1)

cainbibie3 cainbibie3 · Answer 2 · 2021-02-03T19:26:04+01:00

Answer:

Option C is correct.

The solution is (3, -1)

Step-by-step explanation:

Substitution

Given the system of equation:

......[1]

......[2]

We can write equation [2] as;

d = e +4 ....[3]

Using substitution method;

Substitute the value of d in equation [1] we have;

Combine like terms;

Subtract 4 from both sides, we get

2e = -2

Divide both sides by 2 we get;

e = -1

Substitute the value of e = -1 in [1] we have;

d +(-1) = 2

d -1 = 2

Add 1 to both sides of an equation;

d = 3

Therefore, the solution for the given system of equation is, (3, -1)

Solve. {d+e=2d−e=4 Use the substitution method. There are an infinite number of solutions. There is no solution. The solution is (3, −1). The solution is (5, 1).

Respuesta :

Otras preguntas

Solve.
{d+e=2d−e=4
Use the substitution method.

There are an infinite number of solutions.
There is no solution.
The solution is (3, −1).
The solution is (5, 1).