Answer: The common ratio of the given geometric sequence = 6.
Step-by-step explanation:
We are given the given geometric sequence : {3, 18, 108, ...}
Here the first term = [tex]a_1=3[/tex]
The second term = [tex]a_2=ar=18[/tex]
The third term = [tex]a_3=ar^2=108[/tex]
Then common ratio of the above geometric sequence with n terms is given by:-
[tex]r=\dfrac{a_{m+1}}{a_m}=\dfrac{108}{3}=\dfrac{18}{3}=6[/tex]
therefore, the common ratio of the given geometric sequence = 6.
