The equation of a line that passes through the point (0,-1) and has a gradient of -3 is y = -3x - 1
From the question, we have the following points that can be used in our computation:
(x, y) = (0, 1)
Also, we have the slope to be
gradient = -3
Rewrite as
m = -3
The equation of the line is then calculated using the following equation
y = m(x - x₁) + y₁
Where
(x, y) = (0, -1)
m = -3
Substitute the known values in the above equation, so, we have the following representation
y = -3 * (x - 0) - 1
Evaluate
y = -3 * x - 1
So, we have
y = -3x - 1
Hence, the line equation is y = -3x - 1
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