a ship is 50 miles from a lighthouse. the bearing of the lighthouse from the ship is n 30 w. the ship travels due east and calculates the bearing to the lighthouse n 40 w. how far is the ship from the lighthouse after traveling due east?

Respuesta :

The initial 50 miles distance from the lighthouse and the N 30° W and N 40° W bearing of the ship before and after traveling due east, using the law of sines, indicates.

  • After travelling due east the ship is approximately 56.53 miles from the lighthouse.

What is the law of sines?

The law of sines states that in a triangle, the ratio of the length of a side to the sine of the angle opposite that side is the same for each of the three sides of the triangle.

The distance of the ship from the lighthouse = 50 miles

Bearing of the lighthouse from the ship = N 30° W

The direction in which the ship travels = due east

The new bearing to the lighthouse = N 40° W

In the triangle formed by the initial and new locations of the ship and the lighthouse, the interior angles, A, B, C are;

m∠A = 30° + 90° = 120°

m∠B = 90° - 40° = 50°

Therefore; m∠C = 180° - (120° + 50°) = 10°

Angle opposite the initial distance of the ship from the lighthouse = ∠B = 50°

The angle opposite the new distance of the ship from the lighthouse = m∠A = 120°

The law of sines indicate that we have;

[tex]\dfrac{50}{sin(50^{\circ})} = \dfrac{New \, distance}{sin(120^{\circ})}[/tex]

50 × sin(120°) = The new distance of the lighthouse × sin(50°)

The new distance of the lighthouse = 50 × sin(120°)/(sin(50°)) ≈ 56.53

  • The distance of the ship from the lighthouse after travelling due east is approximately 56.53 miles

Learn more about the law of sines here:

https://brainly.com/question/19149891

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