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you push on a 2-kg block initially at rest on a frictionless surface with 10n of force horizontal for 5m on level ground before letting go. the block slides into a loop with a radius of 0.5 m. what velocity will the block have at the top of the loop?

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You push on a 2-kg block initially at rest on a frictionless surface with 10n of force horizontal for 5m on level ground before letting go. the block slides into a loop with a radius of 0.5 m. The velocity will the block have at the top of the loop is determined as 7.071 m/s.

To find the velocity, the given values are,

Mass m = 2 Kg

Force F = 10 N

Displacement = 5m

Radius = 0.5 m

What is Work energy theorem?

The work-energy theorem states that the change in the kinetic energy is equal to the amount of work done.

Energy is ability to do work. To perform work, energy has to be spent. Work is said to be done whenever the force is applied to an object then the object is moved to a certain distance.

According to work energy theorem, the work done on an object is equal to the change in kinetic energy of the object.

So, work done = Kinetic energy

Force × Displacement = 1/2 mv²

Thus, the velocity can be determined as

velocity v = √(2×Force×Displacement/m)

Substituting all the given values,

Velocity, v = [tex]\sqrt{\frac{2*10*5}{2} }[/tex]

v = √50

v = 7.071 m/s.

So, the block's velocity is determined as 7.071 m/s.

Learn more about work energy,

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