The complex Fraction z=(2-[tex]\frac{1}{y}[/tex])/3+[tex]\frac{1}{y}[/tex], is equal to:
4)2y-1/3y+1
writing equations from the question
Q Which expression is equivalent to the complex fraction
z=(2-[tex]\frac{1}{y}[/tex])/3+[tex]\frac{1}{y}[/tex],
1)3y+1/2y-1
2)(2y-1)(3y+1)/y^2
3)y^2/(2y-1)(3y+1)
4)2y-1/3y+1
z=2-[tex]\frac{1}{y}[/tex]/3+[tex]\frac{1}{y}[/tex];
Taking LCM (Lowest Common Multiple)
z=[tex]\frac{2y-1}{y}[/tex]/[tex]\frac{3y+1}{y}[/tex]
As there are fractions being divided by fractions the denominator fraction will get multiplied as a reciprocal with the fraction in the numerator.
z=(2y-1)/y X y/(3y+1)
The y 's are both cancelled out by each other with one being in the numerator and the other as the denominator.
so, z=2y-1 X [tex]\frac{1}{3y+1}[/tex]
z=2y-1/3y+1
thus the answer is option 4)2y-1/3y+1
Learn more about complex numbers at:
brainly.com/question/28007020
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