Given that f(x)=x2−9x and g(x)=x+1, find

The value of the functions are,
f + g = x² - 8x + 1
f - g = x² - 10x - 1
fg = x³-8x²-9x
The expression that established the relationship between the dependent variable and independent variable is referred to as a function. In the function as the value of the independent variable varies the value of the dependent variable also varies.
Given functions are f(x) = x² − 9x and g(x) = x + 1. The values will be calculated as,
f + g = x² − 9x + x + 1
f + g = x² − 8x + 1
f - g = x² − 9x - x - 1
f - g = x² − 10x - 1
f x g = (x² − 9x) x (x + 1)
f x g = (x³ +x ² - 9x² -9x)
f x g = x³ - 8x² - 9x
Therefore, the value of the functions are, f + g = x² - 8x + 1, f - g = x² - 10x - 1, and fg = x³-8x²-9x.
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