A 1400 kg catapul launches a 75 kg boulder at a nearby castle. What is the recoil speed of the catapult if the rock is launched with a velocity of 130 m/s​

Respuesta :

The recoil speed of the catapult is 6.96 m/s.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Mass of the catapult : M = 1400 kg.

Mass of the boulder: m = 75 kg.

Velocity of the rock: v = 130 m/s.

We have to find: recoil speed of the catapult: V = ?

From the principle of conservation of linear momentum:

momentum of the boulder = - momentum of the  catapult

⇒ mv = - MV

⇒ v = -mv/M = - (75 × 130)/1400 m/s = - 6.96 m/s

Negative sign indicates recoil of the catapult is in opposite direction of motion of the boulder.

So, the recoil speed of the catapult is 6.96 m/s.

Learn more about velocity here:

https://brainly.com/question/18084516

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