a hole is bored diametrically through a solid sphere. if the cylindrical wall of the hole is six inches long, what is the remaining volume of the sphere

Respuesta :

Based on the premise that the sphere's radius is irrelevant, the remaining volume is 113.1 cubic inches.

Define the term solid sphere?

  • A sphere has a spherical, symmetrical shape.
  • It is a three-dimensional solid with equal distances between each surface point and the center.

Let the hole's final length be 2L. Let R be the sphere's radius.

Let r represent the hole's radius.

L must equal R; since L≤R.  x² - y² = R²

The outcome can be visualized as a stack with annuli.

Cut a hole in the middle of the object, with the hole's axis corresponding to the x-axis, in a plane. Place the origin as the center.

The inner radius of the annulus is equal to r = √ (R² - L²) for a particular value of x.

x² - y² = R²  is satisfied by the outer radius, y.

The difference between the areas of a circle for all those two radii is the area of the an annulus.

Integrate now:

∫π(R² - x²) - (R² - L²))dx = ∫ π(L² - x²))dx

= π(L²x - x³/3) Put limits -L to +L.

= 4πL³/3

We can see that this does not depends on R irrespective of the final line to assessing the integral.

Thus, the solution, which is roughly 113.1 cubic inches, is confirmed by substituting L= 3 inches, is the remaining volume of the sphere.

To know more about the solid sphere, here

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