The minimum number of integers that must be odd, then, is (A) 1.
So, it is conceivable for the initial two integers to both be even, as in the case of 10 + 16 = 26.
The next two numbers, however, when added together, result in an odd 15 increase, thus one of them must be odd and the other must be even. For instance, 3 + 12 equals 15.
Last but not least, the following two integers add up to 16, which is even, therefore we can have both be even: for instance, 2 + 14 = 16.
The minimum number of integers that must be odd, then, is 1.
Therefore, the minimum number of integers that must be odd, then, is (A) 1.
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Correct question:
Two integers have a sum of 26. when two more integers are added to the first two integers the sum is 41. finally when two more integers are added to the sum of the previous four integers the sum is 57. what is the minimum number of odd integers among the 6 integers?
(a) 1
(b) 2
(c) 3
(d) 4
(e) 5