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A coil of 300 turns, wound on a core of non-magnetic material, has an inductance of 10 mH. Calculate:


a. The flux produced by a current of 5 A;


b. The average value of the e. M. F. Induced when a current of

5 A is reversed in 8 ms (milliseconds).

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(a) The flux produced by a current of 5 A is 1.67 x 10⁻⁴ Wb.

(b) The average value of the E. M. F. Induced when a current of 5 A is reversed in 8 ms is 6.26 V.

What is the flux produced by the current?

The flux produced by a current of 5 A is calculated by applying the following equation.

L = NФ/I

where;

  • N is the number of turns of the coil
  • Ф is the flux produced
  • I is the current
  • L is the self-inductance

Make Ф (flux) the subject of the formula in the above equation;

Ф = LI/N

Ф = (10 x 10⁻³ x 5) / (300)

Ф = 1.67 x 10⁻⁴ Wb

The average value of the E. M. F. Induced when a current of 5 A is reversed in 8 ms.

emf = NdФ/dt

emf = (300 x 1.67 x 10⁻⁴) / (8 x 10⁻³)

emf = 6.26 V

Learn more about emf induced here: https://brainly.com/question/13744192

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