52.5 ml of NaCl of 0.100 m NaCl would be required.
The dilution equation :
M₁ . V₁ = M₂ . V₂
Where, M₁ = Molarity of NaCl = 0.100 m
V₁ = Volume of NaCl = ?
M₂ = Molarity of diluted NaCl = 0.0350 m
V₂ = Volume of diluted NaCl = 150.0 ml
now, we are putting the values ,
0.100 × V₁ = 0.0350 × 150
V₁ = 52.5 ml
So, 52.5 ml of 0.100 m of NaCl would be required to make a 0.0350 m solution of NaCl when diluted to 150.0 ml with the water.
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