The volumes of two similar solids are 210 m3 and 1,680 m3. The surface area of the larger solid is 856 m2. What is the surface area of the smaller solid?

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22-02-2017
Mathematics

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The volumes of two similar solids are 210 m3 and 1,680 m3. The surface area of the larger solid is 856 m2. What is the surface area of the smaller solid?

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calculista calculista · Answer 1 · 2018-08-29T04:29:43+02:00

we know that

[tex] scale \ factor^{3}=\frac {volume\ larger\ solid }{volume\ smaller\ solid} [/tex]

so

Find the value of the scale factor

[tex] volume\ larger\ solid= 1,680\ m^{3} \\ volume\ smaller\ solid= 210\ m^{3} [/tex]

substitute the values in the formula

[tex] scale \ factor^{3}=\frac {1,680 }{210} [/tex]

[tex] scale \ factor^{3}=8 [/tex]

[tex] scale \ factor=\sqrt[3]{8} \\ scale \ factor= 2 [/tex]

Find the surface area of the smaller solid

we know that

[tex] scale \ factor^{2}=\frac {surface\ area\ larger\ solid }{surface\ area\ smaller\ solid} [/tex]

[tex] surface\ area\ larger\ solid =856\ m^{2} \\ scale\ factor =2 [/tex]

[tex] surface\ area\ smaller\ solid= \frac{surface\ area\ larger\ solid}{scale \ factor^{2}} [/tex]

substitute the values

[tex] surface\ area\ smaller\ solid= \frac{856}{2^{2}} [/tex]

[tex] surface\ area\ smaller\ solid=214\ m^{2} } [/tex]

therefore

the answer is

The surface area of the smaller solid is equal to [tex] 214\ m^{2} [/tex]

calculista calculista · Answer 2 · 2018-08-29T04:29:43+02:00

we know that

[tex] scale \ factor^{3}=\frac {volume\ larger\ solid }{volume\ smaller\ solid} [/tex]

so

Find the value of the scale factor

[tex] volume\ larger\ solid= 1,680\ m^{3} \\ volume\ smaller\ solid= 210\ m^{3} [/tex]

substitute the values in the formula

[tex] scale \ factor^{3}=\frac {1,680 }{210} [/tex]

[tex] scale \ factor^{3}=8 [/tex]

[tex] scale \ factor=\sqrt[3]{8} \\ scale \ factor= 2 [/tex]

Find the surface area of the smaller solid

we know that

[tex] scale \ factor^{2}=\frac {surface\ area\ larger\ solid }{surface\ area\ smaller\ solid} [/tex]

[tex] surface\ area\ larger\ solid =856\ m^{2} \\ scale\ factor =2 [/tex]

[tex] surface\ area\ smaller\ solid= \frac{surface\ area\ larger\ solid}{scale \ factor^{2}} [/tex]

substitute the values

[tex] surface\ area\ smaller\ solid= \frac{856}{2^{2}} [/tex]

[tex] surface\ area\ smaller\ solid=214\ m^{2} } [/tex]

therefore

the answer is

The surface area of the smaller solid is equal to [tex] 214\ m^{2} [/tex]