The temperature changes by -3978.88 kelvin.
Here given ,
n = 1
W = 490j
Since the above process is adiabatic, heat is zero. Consequently, internal energy changes are caused by,
ΔU=Q-W
= 0 - 490
=-490 J
Additionally, for monoatomic gas, internal energy changes include,
ΔU=3/2*n*R*ΔT
-490 = 3/2 x n x R x ΔT
-490 = 3/2 x 1 x 0.0821 x ΔT
-490 = 0.12315 x ΔT
ΔT = -490 / 0.12315
ΔT = -3978.88 K
Since the above response has a negative sign, the temperature has decreased.
Therefore,
A reduction in temperature of about ΔT = -3978.88 K has occurred.
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