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what is the internal resistance of a 12.0- vv car battery whose terminal voltage drops to 9.0 vv when the starter draws 76 aa ?

Respuesta :

OneeRa

The internal resistance of the car battery is 0.0395 Ω. The result is obtained by using the formula to find the electromotive of Volts.

How to find the electromotive of Volts?

Electromotive of Volts can be counted by the following formula.

ξ = V + Ir

or

ξ = IR + Ir

Where

  • ξ = EMF or electromotive force of Volts
  • V = potential difference terminal
  • I = current
  • R = load resistance
  • r = internal resistance

We have:

  • Potential difference terminal, V = 12.0 V
  • Electromotive force of Volts, ξ = 9.0 V
  • The current, I = 76 A

What is the internal resistance? (r = ?)

By using the above formula, we get

ξ = V + Ir

Ir = ξ - V

r = (ξ - V)/I

The internal resistance is

r = (9.0 - 12.0)/76

r =  0.0395 Ω

Hence, the internal resistance of car battery is 0.0395 Ω.

Learn more about internal resistance here:

brainly.com/question/13854914

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