what is the potential of the cell when it is prepared using 0.5 m zn(no3)2 solution, hydrogen gas at 1.2 bar and a ph of 5.5?

Respuesta :

The potential of the cell when it is prepared using 0.5 m zn(no3)2 solution, hydrogen gas at 1.2 bar and a ph of 5.5 is 0.4416V

Ecell=E°cell-0.0591/nlog([Zn]*Ph2/[H⁺]²)

=0.76-0.0591/2log(0.5*1.184/3.162*10⁻⁶)²)

=0.4416V

ΔG=-nFE°

n=2,E°=0.76V

=-2*96485*.76

=-146.657 kj

The lightest substance is hydrogen. Hydrogen is a gas of diatomic molecules with the formula H 2 when conditions are normal. It burns easily and is non-toxic, tasteless, colorless, odorless, and odorless. With approximately 75% of all normal matter made up of hydrogen, it is the most prevalent chemical in the universe. Having the atomic number 1 and the letter H, hydrogen is the first chemical element. The lightest substance is hydrogen. Hydrogen has the formula H2 and exists as a gas under normal conditions. It burns easily and is non-toxic, tasteless, colorless, odorless, and odorless.

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