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A quantity x varies directly with the square of y and
inversely with the cube root of z. if x = 6 when y = 2
and z = 8, find the x when y = 1 and z = 27.​

Respuesta :

mhanifa

Answer:

  • x = 1

-----------------------------

Given relation

  • x = ky²/∛z, where k- constant

Given values

  • x = 6, y = 2, z = 8

Find the value of k

  • 6 = k×2²/∛8
  • 6 = k×4/2
  • 3 = k

The equation is now

  • x = 3y²/∛z

Find the x when y = 1 and z = 27

  • x = 3 × 1/∛27 = 3/3 = 1
ANCKPOP

Answer:

x = 1

Step-by-step explanation:

k is the constant of proportionality

Ver imagen ANCKPOP

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