A substance has a molar mass of 60 g/mol with 40.0 percent carbon, 6.7 percent hydrogen, and 53.3 percent oxygen. What is its empirical formula? 1. C3H3O2 2. CHO 3. C2H4O2 4. C2H2O3 5. CH2O 6. C2HO 7. C3H2O2 8. CHO2 9. C2H3O2

Respuesta :

The empirical formula for the given compound is CH₂O. Therefore, option (5) is correct.

What is the empirical formula?

The empirical formula of a compound gives the simplest ratio of the number of different elements present in a compound. The molecular formula can be defined as a multiple of the empirical formula of a compound.

Given, the percent of carbon = 40 % = 40 g

The percent of hydrogen = 6.7 % = 6.7 g

The percent of oxygen = 53.3 % = 53.3 g

The moles of the carbon = 40/12 = 3.33

The moles of hydrogen = 6.7/1 = 6.7

The moles of oxygen = 53.3/16 = 3.33

The ratio of C: H:O  can be written as 3.33: 6.7: 3.33

The simplest ratio can be 1 : 2 : 1

Therefore, the empirical formula of the given compound is CH₂O.

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