Respuesta :

semsee45

Answer:

25.4 L

Step-by-step explanation:

Charles's Law

[tex]\sf \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\quad \textsf{(when pressure is constant and temperature is in kelvin)}[/tex]

where:

  • V₁ = first volume.
  • T₁ = first temperature.
  • V₂ = second volume.
  • T₂ = second temperature.

Given:

  • V₁ = 25 L
  • T₁ = 25.0 °C
  • T₂ = 30.0 °C

Convert Celsius to kelvin.

Kelvin = Celsius + 273.15

[tex]\implies \sf T_1= 25 + 273.15 = 298.15 \;K[/tex]

[tex]\implies \sf T_2 = 30 + 273.15 = 303.15\; K[/tex]

Substitute the given values into the formula:

[tex]\implies \sf \dfrac{25}{298.15}=\dfrac{V_2}{303.15}[/tex]

[tex]\implies \sf V_2 =303.15 \cdot \dfrac{25}{298.15}[/tex]

[tex]\implies \sf V_2 =\dfrac{7478.75}{298.15}[/tex]

[tex]\implies \sf V_2 =25.41925205...L[/tex]

Therefore, the volume of air in the tire if the temperature increases to 30.0 °C is 25.4 L (nearest tenth).

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