8-9. If AG = 2, GF = 5, FE = 3, GB = 6, CD = 7 and GB || FC || ED, find the lengths of the missing sides?
AB=?
BC=?
FC=?
ED=?

Answer:
Step-by-step explanation:
In the given triangle AED, segments GB and FC are parallel to base ED. Points G and F are on segment AE in that order. Lengths AG=2, GF=5, FE=3, GB=6, and CD=7 are given. You want the lengths of AB, BC, FC, and ED.
Segments of transversals crossed by parallel lines are proportional:
AG : GF : FE = AB : BC : CD
2 : 5 : 3 = AB : BC : 7
Multiplying the first ratios by 2 1/3 will give the second ratios:
2 : 5 : 3 = 4 2/3 : 11 2/3 : 7
This lets us conclude ...
AB = 4 2/3
BC = 11 2/3
Corresponding segments of similar triangles are proportional:
AG : GB = FA : FC = AE : ED
2 : 6 = (5+2) : FC = (5+2+3) : ED
We notice the second number in the first ratio is 3 times the first number. That means these ratios are ...
2 : 6 = 7 : 21 = 10 : 30
This lets us conclude ...
FC = 21
ED = 30
The lengths of the missing sides are calculated to be
The parallel lines in the figure created similarity between the dimensions, this makes the ratio of the dimensions equal
The given dimensions that is used to find the missing sides
Solving for AB
AB / CD = AG / FE
AB / 7 = 2 / 3
cross multiplying
3 * AB = 7 * 2
AB = 14/3 = 4.667
Using AB, GF is calculated
AB / BC = AG / GF
14/3 / BC = 2 / 5
cross multiplying
BC = (5 * 14/3) / 2
BC = 35/3 = 11.667
Solving for FC
GB / FC = AG / A'F
6 / FC = 2 / (2 + 5)
cross multiplying
2 * FC = 6 * 7
FC = 42/2 = 21
Solving for ED
GB / ED = AG / AE
6 / ED = 2 / (2 + 5 + 3)
cross multiplying
2 * ED = 6 * 10
ED = 60/2 = 30
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