The ball will land 0.312m away from the base of the table.
The equations of motion are used to establish the relationship between the acceleration, velocity, time, and displacement of a moving object.
The equations of motion are represented in the form of mathematical expressions as follows:
[tex]v = u + at\\S = ut +\frac{1}{2} at^2\\v^2-u^2= 2aS[/tex]
Given, the height of the table, h = 0.75 m
The horizontal speed of the ball, v = 0.8 m/s
The initial speed of the ball, u = 0
From the third equation of motion, calculate the time:
[tex]S = ut +(1/2)at^2[/tex]
[tex]0.75 = \frac{1}{2} (9.8) t^2[/tex]
t = 0.39 sec
The horizontal distance can be calculated from the formula of the velocity:
Horizontal distance = v × t = 0.8 × 0.39 = 0.312 m
Learn more about the equation of motion, here:
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