Write the equation of the line that is perpendicular to the line below and passes through the point (4,-6) write your equation in point-slope form.

The required equation of the line is given as y = -4/3x - 2/3.
Given that,
The equation of the line that is perpendicular to the line below and passes through the point (4,-6).
A line is a straight curve connecting two points or more showing the shortest distance between the initial and final points.
Here,
The slope of the given line = 3/4
So the slope of the perpendicular line = -4/3
Now,
The perpendicular line passes from (4, -6)
The standard form of the equation,
y - y₁ = m [ x - x₁]
Substitute the value in the above expression,
y + 6 = -4/3[x - 4]
y = -4/3x + 16/3 - 6
y = -4/3x - 2/3
Thus, The required equation of the line is given as y = -4/3x - 2/3.
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