Answer:
768
Step-by-step explanation:
Define the variable:
- Let x be the number of eggs Mr Cho received in the beginning.
Given information:
- Mr Cho sold 1/3 of the eggs in the morning.
- Mr Cho sold 320 eggs in the afternoon.
- At the end of the day, Mr Cho found that 1/4 of the eggs were not sold.
Create an equation with the defined variable and the given information:
[tex]\implies x - \dfrac{1}{3}x-320=\dfrac{1}{4}x[/tex]
Solve for x:
[tex]\implies \dfrac{2}{3}x-320=\dfrac{1}{4}x[/tex]
[tex]\implies \dfrac{2}{3}x-320-\dfrac{1}{4}x=\dfrac{1}{4}x-\dfrac{1}{4}x[/tex]
[tex]\implies \dfrac{5}{12}x-320=0[/tex]
[tex]\implies \dfrac{5}{12}x-320+320=0+320[/tex]
[tex]\implies \dfrac{5}{12}x=320[/tex]
[tex]\implies 12 \cdot \dfrac{5}{12}x= 12 \cdot 320[/tex]
[tex]\implies 5x=3840[/tex]
[tex]\implies \dfrac{5x}{5}=\dfrac{3840}{5}[/tex]
[tex]\implies x=768[/tex]
Therefore, Mr Cho received 768 eggs in the beginning.
