To explain further for each of the scenarios on how to solve the problem and show your work (set up the numbers in the equation) is given under.
How many two-apple combos can you create when you have three apples?
We may use the following combination equation to solve this problem: C(n, k) is equal to n! / (k! * (n-k)!. In this instance, the number of apples is n=3, and k=2 apples in each combination). With these values entered into the formula, we obtain:
C(3, 2) = 3! / (2! * (3-2)!) = 3 / 2 = 1.5
Given that a combination is a collection of things chosen without respect to their order, the solution to this puzzle is 1.5. However, because you cannot eat half an apple, the real number of combinations of two apples that may be formed is one.
How many possible combinations of two novels can you create if you have four?
C(n, k)=n!/(k!*(n-k))!
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