The probability that the X is between 72 and 84 is 0.340 , the correct option is (d) .
In the question ,
it is given that ,
The random variable X is said to be normally distributed ,
the mean is given as , μ = 70 , and
standard deviation of normal distribution is (σ) = 10
probability that X is between 72 and 84 is written as P(72 < X < 84)
= P((72 - 70)/10 [tex]<[/tex] Z [tex]<[/tex] (84 - 70)/10)
= P(0.2 < Z < 1.4)
= P(0 [tex]<[/tex] Z [tex]<[/tex] 1.4) – P(0 [tex]<[/tex] Z [tex]<[/tex] 0.2)
From the z table , we get the values as
= 0.4192 – 0.0793
= 0.3399
≈ 0.340
Therefore , The probability that the X is between 72 and 84 is 0.340 , the correct option is (d) .
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