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To simulate a toss of a coin we let the digits 0, 1, 2, 3, and 4 correspond to a head and the digits 5, 6, 7, 8, and 9 correspond to a tail. Consider the following game: We are going to toss the coin until we either get a head or we get two tails in a row, whichever comes first. If it takes us one toss to get the head we win $2, if it takes us two tosses we win $1, and if we get two tails in a row we win nothing. Use the following sequence of random digits: 12975 13258 45144The estimated number of tosses in a single trial of the game is?A)2.0B)15/9C)15/11D)11/7E)7/11

Respuesta :

As per the given probability, the estimated number of tosses in a single trial of the game is 7/11

Probability:

Basically, the term Probability refers the possibility of happening the particular event.

Given,

Here we have to simulate a toss of a coin we let the digits 0, 1, 2, 3, and 4 correspond to a head and the digits 5, 6, 7, 8, and 9 correspond to a tail. And consider the following game: We are going to toss the coin until we either get a head or we get two tails in a row, whichever comes first. If it takes us one toss to get the head we win $2, if it takes us two tosses we win $1, and if we get two tails in a row we win nothing.

While we looking into the given question we have identified that, the total number possible events is 11.

And we have to find the single trial of the game that is 7.

So, the estimated number of tosses in a single trial of the game is written as,

=> 7/11

To know more about Probability here.

https://brainly.com/question/11234923

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