The product is [tex]ZnSO[/tex]₄[tex](aq)[/tex] [tex]+ Fe(s)[/tex] and this is in aqueous form which is formed by the reaction [tex]FeSO[/tex]₄ [tex](aq) + Zn(s)[/tex] .
The reaction given in the question is,
[tex]FeSO[/tex]₄ [tex](aq) + Zn(s)[/tex]
When this net ionic reaction takes place completely it gives a product as
[tex]FeSO[/tex]₄ [tex](aq) + Zn(s)[/tex] ⇒ [tex]ZnSO[/tex]₄[tex](aq)[/tex] [tex]+ Fe(s)[/tex]
Where,
[tex]FeSO[/tex]₄ is Ferrous sulfate that is hydrous
[tex]Zn[/tex] is zinc that is solid
[tex]ZnSO[/tex]₄ is Zinc sulfate that is hydrous
[tex]Fe[/tex] is Iron or Ferrous that is solid
Here,
[tex]Zn[/tex] gets oxidized and [tex]Fe[/tex] gets reduced.
The reduction and oxidation reactions are follows :
Reduction reaction is ,
[tex]Fe[/tex] ² +2e ⟶[tex]Fe[/tex] ⁰
Oxidation reaction is ,
[tex]Zn[/tex] − 2e⁻ ⟶[tex]Zn[/tex] ²
A net ionic equation is a chemical equation of a reaction that lists only the species involved in the reaction. The net ionic equation is commonly used in acid-base neutralization reactions, double displacement reactions, and redox reactions.
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