substitute with the givens to get:
\begin{align*} I&=\dfrac{3.41 \times 10^{-3} \mathrm{~T}}{(4\pi \times 10^{-7} \mathrm{~T\cdot m/A})(10000 \mathrm{~turn/m})}\\ &=0.271 \mathrm{~A} \end{align*}
I
The solenoid's current is 0.272A.
solved from this equations, I=/[tex]\frac{3.41×10⁻³T}{(4π×10⁻⁷T⋅m/A)(10000 turn/m)}[/tex]
Electrical charge carriers, such as electrons, flow as current. From negatives to positive points, current flows. The amperage seems to be the SI unit of measurement for alternating energy (A). One make this process of electrical current traveling through a specific place for one second is refereed to as one amperage of power.
Current is typically represented by the letter I, which comes from the French term intensité du courant (current intensity). The term "current" is frequently used to refer to current intensity. André-Marie Ampère, who gave the electric current unit its name, formulated his force law using the I symbol (1820).
To know more about Current visit:
https://brainly.com/question/13076734
#SPJ4
