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Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is selected. Find the probability of selecting a three and then selecting a fiveThere are 4 threes in the deck so the probability of selecting a three is 4/52. Then, for the second draw, there are 4 fives as well but, since you already selected a card and didn't replace it, there are now only 51 cards in the deck so the probability of selecting a five is 4/51The probability of both events happening is the product of the two individual probabilities so 4/52 * 4/51 = 16/2652 = 4/663 = 0.6%

Respuesta :

The probability of selecting a three and then selecting a five is 0.6%

What is meant by probability?

Probability is a branch of mathematics that deals with numerical descriptions of how likely an event or statement is to occur.

Probability is computed by dividing the number of possible outcomes by the total number of possible outcomes. Probability and odds are two distinct ideas. Odds are calculated by dividing the probability that something will occur by the probability that it will not occur.

Because there are four threes in the deck, the probability of picking one is 4/52.

Then, for the second draw, there are four fives as well, but because you already chose a card and did not replace it, there are only 51 cards in the deck, therefore the likelihood of drawing a five is 4/51.

The product of the two individual probabilities is the likelihood of both events occurring.

So,

(4/52) × (4/51)= 16/2652

= 4/663

= 0.6%

Hence,  the probability of selecting a three and then selecting a five is 0.6%

To know more about probability, visit:

https://brainly.com/question/11234923

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