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Write the net ionic equation for this reaction occuring in water: Calcium sulfide and iron(II) bromide are mixed to form iron(II) sulfide and calcium bromide.
1. Sr2+ + S2− + Fe2+ + 2 Br− → FeS + CaBr2
2. No reaction occurs
3. S 2− + Fe2+ → FeS
4. Ca2+ + 2 Br− → CaBr2
5. S 2− + FeBr2 → FeS + 2 Br−
6. CaS + 2 Br− → S 2− + CaBr2
S 2− + Fe2+ → FeS

Respuesta :

Option 3. S 2− + Fe2+ → FeS is the correct answer. The net ionic equation for this reaction occurring in water is S 2− + Fe2+ → FeS

A chemical reaction in which one of the products formed is insoluble and separates out as a precipitate is known as a precipitation reaction. The met ionic equations of a precipitation reaction can be written by removing spectator ions from the total ionic equation of the precipitation reaction.

The balanced molecular equation for the reaction between calcium sulfide and iron (II) bromide to form iron (II) sulfide and calcium bromide is,

CaS(aq) + FeBr_2(aq) \to FeS(s) + CaBr_2

The total ionic equation will be

[tex]Ca^{2+}(aq) + S^{2-}(aq) + Fe^{2+}(aq) + 2Br^-(aq) \to FeS(s) + Ca^{2+}(aq) + 2Br^-(aq)[/tex]

After removing spectator ions, we get the following net ionic equation:

Fe^{2+}(aq) + S^{2-}(aq) \to FeS(s)

Learn more about reactions:

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