1. F v (D → T)
2. V F
3. D
∴ T
4. D → T (Disjunctive syllogism 1,2)
5. T ( Modus Ponens 3,4)
2. P → (cu → T)
2. Q → (T → E)
3. P
4. Q
∴ Cu → E
5. Cu → T (modus ponens 1,3)
6. T → E ( modus ponens 2,4)
7. Cu → E (Hypothetical syllogism 5,6)
3. 1. ~ X → [~X → (y → X)]
2. ~ X
∴ ~ y
3. ~X → (y → X) (modus ponens 1,2)
4. y → X ( modus ponens 2,3)
5. ~ y ( modus tollens 2,4)
4. 1. k → (L→m)
2. m v k
3. ~m
∴ ~L
4. K (disjunctive syllogism 2,3)
5. L → m (modus ponens 1,4)
6. ~ L (modus tollens 3,5)
5. 1. ~S → D
2. ~S v (~D→K)
3. ~ D
∴ K
4. ~(~S) (Modulas tollens 1,3)
5. S ( Double nojection 4)
6. ~D→K (Disjunctive syllogism 2,5)
7. K (Modus ponenes 3,6)
Hence we get the required answer.
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