using your calculations, identify the limiting reactant of your reaction and determine the maximum amount (in moles) of carbon dioxide that could be produced.'

Respuesta :

In the given reaction, oxygen is the limiting reagent and carbon disulfide is the excess reagent.

What is Iimiting reagent?

  • A limiting reagent (or limiting reactant or limiting agent) in a chemical reaction is a reactant that is completely consumed when the chemical reaction is completed. [1][2]
  • The amount of product formed is limited by this reagent, as the reaction will not proceed without it. When one or more other reagents are present in excess of what is required to react with the limiting reagent, they are called excess reagents or excess reactants (sometimes abbreviated "xs").
  • Since the theoretical yield is defined as the amount of product obtained when the limiting reagent is completely reacted, the limiting reagent must be identified in order to calculate the yield of the reaction.
  • Given the balanced chemical equation that describes the reaction, there are several equivalent methods for identifying the limiting reagent and assessing the excess of other reagents.

According to our question-

a) The limiting reactant is Oxygen  

b) There will remain 0.667 moles of Carbon disulfid  

c) 0.333 moles of Carbon dioxide and 0.667 moles of Sulfur dioxide will be formed.  

1 mole of Carbon disulfide need 3 moles of Oxygen to produce 1 moles of Carbon dioxide and 2 moles of sulfur dioxide.  

Number of moles of  Carbon disulfide = 1.00 mol  

Number of moles of Oxygen = 1.00 mol    

Calculate the limiting reactant    

Oxygen is the limiting reactant. It will completely be consumed.(1.00 mol).  

(B) Carbon disulfide is excess reactant. There will react with

Carbon disulfide react with 0.33 moles of Oxygen.

The remaining excess reagent:

0.667 moles of Carbon disulfide will remains.  

Calculate moles of products:

1 mole of Carbon disulfide need 3 moles of Oxygen to produce 1 moles of Carbon dioxide and 2 moles of sulfur dioxide.  

For 1.00 mol of oxygen =  1.00/3 = 0.333 moles Carbon dioxide.  

For 1.00 mol of Oxygen  = 1.00 /(3/2) = 0.667 moles of sulfur dioxide.

Hence, In the given reaction, oxygen is the limiting reagent and carbon disulfide is the excess reagent.

learn more about limiting reagents click here:

https://brainly.com/question/14222359

#SPJ4