The equivalent resistance of the circuit is d)11.5 ohms. So, correct option is d.
We know very well that net resistance when resistors are connected in parallel and net resistance when resistors are connected in series is different.
So, we can see that three 4.7kΩ are connected in parallel.
So, using formula of net resistance in parallel
=>1/Rₙ=(1/R₁)+(1/R₂)+(1/R₃)
Therefore,1/Rₙ=1/4.7+(1/4.7)+(1/4.7)
=>1/Rₙ=3/4.7kΩ
=>Rₙ=4.7/3kΩ
=>Rₙ=1.5kΩ
Now, we have net resistance of three resistors.
Now, remaining three resistors are now connected in series
So, using formula of net resistance when resistors are connected in series=Rₙ=R₁+R₂+R₃
So, three resistors have resistance 4.7kΩ,1.5kΩ,5.2kΩ respectively
Therefore, Rₙ=4.7+1.5+5.2=11.5kΩ.
Hence, equivalent resistance is d)11.5kΩ.
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(Complete question) is:
Calculate the equivalent resistance in ohms of the following circuit : a)18100kΩ
b)11470kΩ
c)18.1kΩ
d)11.5kΩ
