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calculate the maximum energy that a 3-mev alpha particle could transfer to an electron in a single collision. calculate the maximum energy that a 3-mev pion could transfer to an electron in a single collision. note: make sure you understand why there is a difference.

Respuesta :

The maximum energy that an alpha particle can transfer is 1.63 KeV.

let mass of electron, Me = 1

let mass of proton, Mp = 1836Me = 1836

let mass of alpha particle, Ma = 4Mp = 7344

And mass of the pion,  M = 66.41Me

(a) The maximum energy transferred to an electron in a single collision will be calculated as

[tex]Q_{max} = \frac{4mME}{(M+m)^{2} }[/tex]

= [tex]\frac{4(1)(7344)(3MeV)}{(1+7344)^{2} }[/tex]

= 0.00163 MeV

= 1.63 KeV

(b) The electrons are called the subatomic particles. The electrons have one of the symbol of e-and β-. The electrons are the first generation of the Lepton particles. These are generally describe the elementary particles. These particles do not have components and substructure.

Hence, maximum energy that an alpha particle can transfer is 1.63 KeV.

To know more about alpha particle here:

https://brainly.com/question/18648917

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