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A person is swimming 1.3 m beneath the surface of the water in a swimming pool. A child, standing on the diving board, drops a ball into the pool, directly above the swimmer. The swimmer sees the ball dropped from a height of 4.1 m above the water. From what height was the ball actually dropped? Express your answer in meters.

Respuesta :

The ball was actually dropped from a height of 5.453 meters.

What is refractive index?

It is the ratio of the speed of light in a vacuum to that in a second medium with a higher density. The symbol n or μ is more frequently used to represent the refractive index variable.

Given in the question,

The apparent depth ([tex]v[/tex]) = 4.1 m

The depth of the person = 1.3 m

Actual depth ([tex]u[/tex]) = ?

We know,

Refractive index of air ([tex]n_{w}[/tex]) = 1

Refractive index of water ([tex]n_{a}[/tex]) = 1.33

We also know,

    [tex]\frac{u}{v} =[/tex] [tex]\frac{n_{w} }{n_{a} }[/tex]

or, [tex]u=v\frac{n_{w} }{n_{a} }[/tex]

Substituting the values in the above equation we get,

[tex]u[/tex] = 4.1×1.33

Hence, [tex]u[/tex] = 5.453 m

So, the actual depth is 5.453 meters.

To know more about speed of light please click here, https://brainly.com/question/104425

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