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when alpha particles of kinetic energy e are incident on nuclei of gold atoms, the smallest distance between an alpha particle and a nucleus is x. what is the smallest separation distance when the alpha particle kinetic energy is doubled to 2e

Respuesta :

smallest separation distance when the alpha particle kinetic energy is doubled to 2e is x/2.  

what is distant of closest aproach?

The distance of closest approach of two objects is the distance between their centers when they are externally tangent. The objects may be geometric shapes or physical particles with well defined boundaries

At distance of closest approach speed of -particles is zero.At the instant of closest approach the initial kinetic energy of the particle will be completely converted into electric potential energy

  • kinetic energy is inversly proportional to distance.so if energy increases distance decreases by two

learn more about distance of closest aprroach:https://brainly.com/question/14696284

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