contestada

Two balls are dropped from rest from the same height. One of the balls is dropped 1 s after the other. a. Find the distance that separates the two balls 2 s after the second ball is dropped. b. State what happens to the distance separating the balls as time goes on.

Respuesta :

Two balls are dropped from the same height at  1 second interval of time. The separation between the two balls after 2 seconds of the drop of the 1st ball is 14.7 m

How is it calculated?

For the motion of first ball ,

u = 0

a = g

t₁ = 2 s

∴  The distance travelled by the first ball in 2 s

S₁ = [tex]\frac{1}{2}[/tex] g t₁²

∴  S₁ = [tex]\frac{1}{2}[/tex] × 9.8 × (2)²

∴ S₁ = 4.9 × 4

∴ S₁ = 19.6 m

For the motion of second ball ,

u = 0

a = g

t₂ = 2-1 = 1 s

∴  The distance travelled by the second ball in 1 s

S₂ = [tex]\frac{1}{2}[/tex] g t₂²

∴  S₂ = [tex]\frac{1}{2}[/tex] × 9.8 × (1)²

∴ S₂ = 4.9 × 1

∴ S₂ = 4.9  m

Separation between the two balls = S₁ - S₂

∴ Separation = 19.6 - 4.9

∴ Separation = 14.7 m

The distance separating the balls as time goes on is 14.7 m

What is distance?

  1. The distance between two points in physical space is the length of the straight line between them, the shortest possible path.
  2. This is the usual meaning of distance in classical physics, including Newtonian mechanics.
  3. Straight-line distance is mathematically formalized as Euclidean distance in 2D and 3D space.

Can learn more about separation distance from https://brainly.com/question/11327563

#SPJ4

Otras preguntas