At a distance of 0.3 inches from the pipe wall, the shear stress is 0.06012 lb/ft2. At a distance of 0.5 inches from the pipe wall, there is no shear stress.
Assume that the pipe has a pressure drop of 0.6 psi per foot, a length of 12 feet, and a diameter of 1 inch.
In a circular pipe, the pressure drop per unit length is given as; make shear stress () the subject of the formula.
Shear tension in part (a) at 0.3 inches from the pipe wall
P = 0.6 psi/ft P, in lb/ft2 = 0.6 x 144 = 86.4 lb/ft2 Radius of the pipe = 0.5 -in r = 0.5 -0.3 = 0.2-in = 0.0167 ft
Shear stress in part (b) at a distance of 0.5 in from the pipe wall is equal to zero.
Learn more about stress here-
https://brainly.com/question/13261407
#SPJ4
